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Compare the Triplets (Python 3)

  • URL : https://www.hackerrank.com/challenges/compare-the-triplets/problem

  • Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from 1 to 100 for three categories: problem clarity, originality, and difficulty.
  • The rating for Alice’s challenge is the triplet a = (a[0], a[1], a[2]), and the rating for Bob’s challenge is the triplet b = (b[0], b[1], b[2]).

  • The task is to find their comparison points by comparing a[0] with b[0], a[1] with b[1], and a[2] with b[2].
    • If a[i] > b[i], then Alice is awarded 1 point.
    • If a[i] < b[i], then Bob is awarded 1 point.
    • If a[i] = b[i], then neither person receives a point.
  • Comparison points is the total points a person earned.
  • Given a and b, determine their respective comparison points.

  • Example
    • a = [1, 2, 3]
    • b = [3, 2, 1]

    • For elements 0, Bob is awarded a point because a[0] .
    • For the equal elements a[1] and b[1], no points are earned.
    • Finally, for elements 2, a[2] > b[2] so Alice receives a point.
  • The return array is [1, 1] with Alice’s score first and Bob’s second.

  • Function Description
    • Complete the function compareTriplets in the editor below.
    • compareTriplets has the following parameter(s):
      • int a[3]: Alice’s challenge rating
      • int b[3]: Bob’s challenge rating
  • Return
    • int[2]: Alice’s score is in the first position, and Bob’s score is in the second.
  • Input Format
    • The first line contains 3 space-separated integers, a[0], a[1], and a[2], the respective values in triplet a.
    • The second line contains 3 space-separated integers, b[0], b[1], and b[2], the respective values in triplet b.
  • Constraints
    • 1 ≤ a[i] ≤ 100
    • 1 ≤ b[i] ≤ 100

문제풀이

  • a,b의 배열의 원소의 크기를 확인후, 더 큰쪽에 점수를 +1씩 하는 함수를 작성
  • 배열의 index를 for문으로 돌려서 if문으로 더 큰쪽에 +1를 하는 코드를 작성 후 해당 점수들을 return하는 함수를 작성하였다.
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def compareTriplets(a, b):
    alice = 0
    bob = 0
    for i in range(len(a)):
        if a[i] > b[i]:
            alice += 1
        elif a[i] < b[i]:
            bob += 1
    return alice, bob
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compareTriplets([1,2,3],[3,2,1])
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(1, 1)
This post is licensed under CC BY 4.0 by the author.