Finding the percentage (Python 3)

• URL : https://www.hackerrank.com/challenges/finding-the-percentage/problem

• The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.

• Example
  • marks key : value pairs are
  • ‘alpha’ : [20, 30, 40]
  • ‘beta’ : [30, 50, 70]
  • query_name : ‘beta’

• The query_name is ‘beta’. beta’s average score is (30 + 50 + 70) / 3 = 50.0.

• Input Format
  • The first line contains the integer n, the number of students’ records. The next n lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query.
• Constraints
  • 2 <= n <= 10
  • 0 <= marks[i] <= 100
  • lenth of marks array = 3
• Output Format
  • Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.

문제풀이

• 이름과 숫자가 주어지고, 마지막에 입력된 이름에 대해 숫자에 대한 평균을 구하는것
• sum과 len 함수를 이용하여 평균을 구하였다.

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if __name__ == '__main__':
    n = int(input())
    student_marks = {}
    for _ in range(n):
        name, *line = input().split()
        scores = list(map(float, line))
        student_marks[name] = scores
    query_name = input()
    print('%0.2f' % (sum(student_marks[query_name])/len(student_marks[query_name])))

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 2
 Harsh 25 26.5 28
 Anurag 26 28 30
 Harsh


26.50