Posts Mod Divmod (Python 3)
Post
Cancel

Mod Divmod (Python 3)

1
2
>>> print divmod(177,10)
(17, 7)
  • Here, the integer division is 177/10 => 17 and the modulo operator is 177%10 => 7.

  • Task
    • Read in two integers, a and b, and print three lines.
    • The first line is the integer division a//b (While using Python2 remember to import division from future).
    • The second line is the result of the modulo operator: a%b.
    • The third line prints the divmod of a and b.
  • Input Format
    • The first line contains the first integer, a, and the second line contains the second integer, b.
  • Output Format
    • Print the result as described above.

문제 해설

  • python 내장 함수중에 divmod에 대한 이야기입니다.
  • a, b가 입력되면
  • 첫번째 줄엔 a//b 즉, a 나누기 b의 몫을 출력 (177 / 10 -> 17)
  • 두번째 줄엔 a%b 즉, a 나누기 b의 나머지를 출력 (177 / 10 -> 7)
  • 세번째 줄엔 divmod(a, b)를 하여 (17, 7)을 출력 입니다.
  • 아주 쉬운 문제 입니다.
1
2
3
4
5
a = int(input())
b = int(input())
print(a//b)
print(a % b)
print(divmod(a, b))
1
2
3
4
5
6
7
 177
 10


17
7
(17, 7)
1
2
x**3 + x**2 + x + 1 == y
1
True
1
2
x = 1
y = 4
1
f = x**3 + x**2 + x + 1
1
f
1
4
1
eval
1
<function eval(source, globals=None, locals=None, /)>
1
This post is licensed under CC BY 4.0 by the author.