URL : https://www.hackerrank.com/challenges/itertools-combinations-with-replacement/problem
- This tool returns r length subsequences of elements from the input iterable allowing individual elements to be repeated more than once.
Combinations are emitted in lexicographic sorted order. So, if the input iterable is sorted, the combination tuples will be produced in sorted order.
- Sample Code
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>>> from itertools import combinations_with_replacement >>> >>> print list(combinations_with_replacement('12345',2)) [('1', '1'), ('1', '2'), ('1', '3'), ('1', '4'), ('1', '5'), ('2', '2'), ('2', '3'), ('2', '4'), ('2', '5'), ('3', '3'), ('3', '4'), ('3', '5'), ('4', '4'), ('4', '5'), ('5', '5')] >>> >>> A = [1,1,3,3,3] >>> print list(combinations(A,2)) [(1, 1), (1, 3), (1, 3), (1, 3), (1, 3), (1, 3), (1, 3), (3, 3), (3, 3), (3, 3)]
- Task
- You are given a string S.
- Your task is to print all possible size k replacement combinations of the string in lexicographic sorted order.
- Input Format
- A single line containing the string S and integer value k separated by a space.
- Constraints
- 0 < k <= len(s)
- The string contains only UPPERCASE characters.
- Output Format
- Print the combinations with their replacements of string S on separate lines.
문제 풀이
- 아마 combinations_with_replacement를 사용하는것이고, 앞에서 배운 itertools의 메서드들이 다른것을 설명하는듯 싶다.
- 주어진 문자열 s에대해 k갯수만큼 끊어서 나오는 모든 조합의 수를 생성
- 이번엔 combinations_with_replacement를 사용하는것
- 로직은 앞에 것들과 똑같다.
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from itertools import combinations_with_replacement
s ,k = input().split()
s = sorted(s)
k = int(k)
from itertools import combinations_with_replacement
c = list(combinations_with_replacement(s,k))
for i in c:
print(''.join(i))
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HACK 2
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